
Solution: there are only 9 possible numbers for the first digit (1-9)
there are 10 possible digits for the last two digits (0-9)
To find the answer: 9x10x10=900 possible three digit numbers
David Dempster
This blog belongs to Mr. Bennet's Applied Math 40S Class from the DRCSS in sunny Dauphin, Manitoba.
thanks for the post Dave, now did you really answer your own question? i.e what is the probability?
ReplyDelete1 out of nine hundred
ReplyDeletesorry that post was me david im just with christa on her blog cus we doing homework together... didnt realize i was still on hers sorry but that was my answer not hers
ReplyDeleteyou guys are funny
ReplyDelete